A 1.5 kv power line runs to a residential area, where atransformer with 1000 tur

Question

A 1.5 kv power line runs to a residential area, where atransformer with 1000 turns on its primary coil steps down thevoltage to 240v. How many turns are on the secondary coil of thetransformer? An ideal transformer steps up 8.0v to 2000v, and the 4000 turnsecondary coil caries 2.0A. A. Find the number of turns on the primary coil B. Find the current in the primary Can someone show me the steps and explain? A 1.5 kv power line runs to a residential area, where atransformer with 1000 turns on its primary coil steps down thevoltage to 240v. How many turns are on the secondary coil of thetransformer? An ideal transformer steps up 8.0v to 2000v, and the 4000 turnsecondary coil caries 2.0A. A. Find the number of turns on the primary coil B. Find the current in the primary Can someone show me the steps and explain?

Explanation / Answer

   No. of turns in primary / no. of turns insecondary   =   primary voltage /secondary voltage    NP /NS   =   VP /VS    a.   1000 /NS    =   1.5 *103 / 240       =>   No.of turns in secondarycoil   =   NS   =   1000* 240 / 1.5 *103   =   160   turns    b.   A.               NP/ 4000   =   8.0 /2000             NP   =   8.0* 4000 /2000   =   16   turns          B.   IP/ IS   =   VS /VP                IP   =   2.0* 2000 /8.0   =   500.0   A                IP   =   2.0* 2000 /8.0   =   500.0   A

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