A 1.5 kg object is initially at rest on a horizontal frictionless surface and is
ID: 1444985 • Letter: A
Question
A 1.5 kg object is initially at rest on a horizontal frictionless surface and is attached to an initially unstretched spring with a force constant of 35 N/m and negligible mass. A constant horizontal force of 364.375 N is applied to the object. Determine the following when the object has slide a distance 0.25 m: the work done by the applied force J, the energy stored in the spring J, the object's final kinetic energy J, and the object's final speed m/s. A 0.2 kg mass is dropped from rest on to a vertical spring with force constant of 1.6 N/m and negligible mass from a height of 0.7 m above the spring. What is the maximum distance the spring will be compressed? m.Explanation / Answer
W = F*d = 364.375*0.25 = 91.094 J
Est = 1/2 kx^2 = 1/2 *35*0.25^2 = 1.094 J
Ke= W-Est = 91.094-1.094 = 90J
1/2 mV^2 = 90
V = sqrt(180/1.5) = sqrt(120) = 10.95 m/s
1/2 kx^2 =mg(h+x), 0.8*x^2=1.96*0.7+1.96x, solve it we have x = 3.02 m
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