5) A person who normally weighs 200 pounds is standing on a scaleinside an eleva

Question

5) A person who normally weighs 200 pounds is standing on a scaleinside an elevator. The
elevator is moving upwards with a speed of 7 m/s, and then beginsto decelerate at a rate of 5
m/s2. Before the elevator begins to decelerate, the reading of thescale is _________, and while
the elevator is slowing down, the reading of the scale is________.
A) 200 pounds, 100 pounds
B) greater than 200 pounds, 0 pounds
C) less than 200 pounds, 100 pounds
D) greater than 200 pounds, 100 pounds
E) none of the above

Please explain how you arrived at the answer. Thanks!

Explanation / Answer

Before the elevator starts to decelerate, the reading on the scaleis 200lbs, since there is not acceleration only constant speed. mg-N=ma N=m(g-a)               200lbs=90.718kg N=90.718(9.8-5) N=90.718*4.8= 435.4464 newtons. 435.4464 newtons.= 97.9lbs almost 100lbs   SO theanswer is A

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