A current-carrying wire 0.50 m long is positionedperpendicular to a uniform magn

Question

A current-carrying wire 0.50 m long is positionedperpendicular to a uniform magnetic field. If the current is 10.0 Aand there is a resultant force of 3.0 N on the wire due to theinteraction of the current and field, what is the magnetic fieldstrength? A current-carrying wire 0.50 m long is positionedperpendicular to a uniform magnetic field. If the current is 10.0 Aand there is a resultant force of 3.0 N on the wire due to theinteraction of the current and field, what is the magnetic fieldstrength?

Explanation / Answer

length L = 0.5 m current i = 10 A force F = 3 N we know force on current carrying wireF = BiL from this mag.field B = F / iL                               = 0.6 T

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