A coil is connected to a 120 V rms, 60 Hz line. The average powersupplied to the

Question

A coil is connected to a 120 V rms, 60 Hz line. The average powersupplied to the coil is 52 W, and therms current is 1.5 A. (a) Find the power factor.
1

(b) Find the resistance of the coil.
2

(c) Find the inductance of the coil.
3 H

(d) Does the current lag or lead the voltage?
4 The current lags the voltage.
The current leads thevoltage.    


(e) Support your answer to Part (d) by determining the phase angle?
5° (a) Find the power factor.
1

(b) Find the resistance of the coil.
2

(c) Find the inductance of the coil.
3 H

(d) Does the current lag or lead the voltage?
4 The current lags the voltage.
The current leads thevoltage.    


(e) Support your answer to Part (d) by determining the phase angle?
5° 4 The current lags the voltage.
The current leads thevoltage.    
4 The current lags the voltage.
The current leads thevoltage.    
4

Explanation / Answer

Average power = rms voltage * rms current * power factor from this power factor = 52 / ( 120 * 1. 5 )                                   = 0.2888 Impedence Z = V / i                      = 120 / 1.5                      = 80 ohm we know power factor = R / Z from this resistance R = Z * power factor                                  = 23.11 ohm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.