A simple pendulum is 2.00 m long. (a) What is the period of simple harmonicmotio

Question

A simple pendulum is 2.00 m long. (a) What is the period of simple harmonicmotion for this pendulum if it is hanging in an elevatoraccelerating upward at 8.00m/s2?
1 s
(b) What is its period if the elevator is accelerating downward at8.00 m/s2?
2 s
(c) What is the period of simple harmonic motion for the pendulumif it is placed in a truck that is accelerating horizontally at8.00 m/s2?
3 s (a) What is the period of simple harmonicmotion for this pendulum if it is hanging in an elevatoraccelerating upward at 8.00m/s2?
1 s
(b) What is its period if the elevator is accelerating downward at8.00 m/s2?
2 s
(c) What is the period of simple harmonic motion for the pendulumif it is placed in a truck that is accelerating horizontally at8.00 m/s2?
3 s

Explanation / Answer

Length L = 2 m accleration a = 8 m / s ^ 2 period T = 2 [ L / ( a + g ) ]               = 2.106 s (b). period T = 2 [ L / ( g - a ) ]                     = 6.619 s

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