A simple pendulum is 2.00 m long. (a) What is the period of simple harmonicmotio

Question

A simple pendulum is 2.00 m long. (a) What is the period of simple harmonicmotion for this pendulum if it is hanging in an elevatoraccelerating upward at 5.00m/s2?
1 s
(b) What is its period if the elevator is accelerating downward at5.00 m/s2?
2 s
(c) What is the period of simple harmonic motion for the pendulumif it is placed in a truck that is accelerating horizontally at5.00 m/s2?
3 s
(a) What is the period of simple harmonicmotion for this pendulum if it is hanging in an elevatoraccelerating upward at 5.00m/s2?
1 s
(b) What is its period if the elevator is accelerating downward at5.00 m/s2?
2 s
(c) What is the period of simple harmonic motion for the pendulumif it is placed in a truck that is accelerating horizontally at5.00 m/s2?
3 s

Explanation / Answer

a) Here we have             T = 2 [ L / g+a ]                 = 2 * 3.14 * 2 / 9.8 + 5                 = 2.308 s b) Here we have             T = 2 [ L / g-a ]                 = 2 * 3.14 * 2 / 9.8- 5                 = 4.053 s c) ax = 5 m/s2     ay = -9.8m/s2 ==> a = ax2 + ay2 = 11.0 m/s2      T = 2 [ L / a ]                 = 2 * 3.14 * 2 / 11                 = 2.677 s

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