In a television set the power needed to operate thepicture tube is 95 W and is d

Question

In a television set the power needed to operate thepicture tube is 95 W and is derived from the secondary coil of atransformer. There is a current of 5.3mA in the secondary coil. Theprimary coil is connected to a 120-V receptacle. Find the turnsratio Ns/Np of the transformer. This is what I have, someone please check my work to make sureI answered right. I have to turn this in for a grade. I will ratewell: P=95W= power needed to operate picture tube derived fromsecondary coil Is=5.3mA=current of secondary coil Vp=120V=voltage of primary coil Ps=IsVs, so Vs=Ps/Is=95W/(5.3*10^(-6) A)=17.92*10^6=Vs Ns/Np=Vs/Vp=(17.92*10^6V)/120V=1.49*10^5=Ns/Np Just want to make sure I did this right and have the rightanswer In a television set the power needed to operate thepicture tube is 95 W and is derived from the secondary coil of atransformer. There is a current of 5.3mA in the secondary coil. Theprimary coil is connected to a 120-V receptacle. Find the turnsratio Ns/Np of the transformer. This is what I have, someone please check my work to make sureI answered right. I have to turn this in for a grade. I will ratewell: P=95W= power needed to operate picture tube derived fromsecondary coil Is=5.3mA=current of secondary coil Vp=120V=voltage of primary coil Ps=IsVs, so Vs=Ps/Is=95W/(5.3*10^(-6) A)=17.92*10^6=Vs Ns/Np=Vs/Vp=(17.92*10^6V)/120V=1.49*10^5=Ns/Np Just want to make sure I did this right and have the rightanswer Just want to make sure I did this right and have the rightanswer

Explanation / Answer

In an ideal transformer, the induced voltage in the secondarywinding (VS) is in proportion to the primaryvoltage (VP), and is given by the ratio of thenumber of turns in the secondary (NS) to thenumber of turns in the primary (NP) asfollows: (Vs/Vp) = (Ns/Np)----------(1) the power needed to operate the picture tube is Ps= 95 W the current in the secondary coil is Is = 5.3 mA =5.3 * 10-3 A we know that Ps = Vs * Is or Vs = (Ps/Is) The primary coil is connected to a Vp = 120-Vreceptacle substituting the above values in equation (1) we get the valueof (Ns/Np). or Vs = (Ps/Is) The primary coil is connected to a Vp = 120-Vreceptacle substituting the above values in equation (1) we get the valueof (Ns/Np).

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