You perform a statistical test (e.g., chi-square) and find that the observed and

Question

You perform a statistical test (e.g., chi-square) and find that the observed and expected genotype frequencies are different. How would you interpret your results?

a. This population is not in Hardy-Weinberg equilibrium because there is an excess of homozygotes. A possible cause is inbreeding. b. This population is not in Hardy-Weinberg equilibrium because there are an excess of homozygotes. A possible cause is negative assortative mating. c. This population is not in Hardy-Weinberg equilibrium because there are an excess of heterozygotes. A possible cause is negative assortative mating. d. This population is in Hardy-Weinberg equilibrium. e. This population is not in Hardy-Weinberg equilibrium because there is an excess of heterozygotes. A possible cause is inbreeding.

Explanation / Answer

a). . This population is not in Hardy-Weinberg equilibrium because there is an excess of homozygotes. A possible cause is inbreeding.

Reason:

Inbreeding results in decreased heterozygous alleles and increase in homozygous alleles. This results in increased chances of inheriting the lethal to deleterious alleles or the recessive alleles, which would cause increase in genetic disorders and decrease in allelic diversity. The increase in homozygotic frequency is mainly due to non- random mating between closely related individuals that reduces heterozygotic frequency. This increase in frequency of the homozygotes is mainly trigger exposure of deleterious recessive alleles to natural selection therefore final mean fitness of the population will be decreased often referred as inbreeding depression & the observed and expected genotype frequencies are different. This population is not in Hardy-Weinberg equilibrium because there is an excess of homozygotes.

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