What must the charge (sign and magnitude) ofa 1.45 g particle be for it to remai

Question

What must the charge (sign and magnitude) ofa 1.45 g particle be for it to remain balanced against gravitywhen placed in a downward-directed electric field of magnitude650 N?C?     Q      =C b)What is the magnitude of an electric fieldin which the electric force it exerts on a proton is equal inmagnitude to the proton's weight?    E          =N/C What must the charge (sign and magnitude) ofa 1.45 g particle be for it to remain balanced against gravitywhen placed in a downward-directed electric field of magnitude650 N?C?     Q      =C b)What is the magnitude of an electric fieldin which the electric force it exerts on a proton is equal inmagnitude to the proton's weight?    E          =N/C

Explanation / Answer

(a)        Since thecharge must balanced by the gravity and downward electric field thecharge must -ve          Then fromequllibrium   mg = Eq                                                q = mg / E                                                    =1.45*10-3kg*9.8m/s2 / 650 N/C                                                    =21 *10-6 C               Then the charge is q = -21 *10-6 C (b) If the proton balanced by the electricfiled then                                        mg = Eq                                           E = mg / q                                               =(1.672*10-27kg)(9.8m/s2) /(1.602*10-19C)                                                     =10.22*10-8N/C                        

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