What must the charge (sign and magnitude) of a particle of mass 1.50 g be for it

Question

What must the charge (sign and magnitude) of a particle of mass 1.50 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C?
Use 9.81 m/s^2 for the magnitude of the acceleration due to gravity.


Part B
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
Use 1.67×10-27 kg for the mass of a proton, 1.60×10-19 C for the magnitude of the charge on an electron, and 9.81 m/s^2 for the magnitude of the acceleration due to gravity.

Explanation / Answer

A.

we have,

qE = mg

q x 680 = 0.0015 x 9.81

a.

Magnitude of Charge q = 2.164 x 10-5 C (or 21.64 C)

b

Sign should be negative ( as then only the forces would be able to balance each other and be in opposite direction)

B.

qE = mg

E = mg/q

= (1.67×10-27 x 9.81)/(1.60×10-19)

= 1.024 x 10-7 N/C

MAgnitude of electric field E = 1.024 x 10-7 N/C

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