Two 34 -C charges are attached to the oppositeends of a spring with a spring con

Question

Two 34-C charges are attached to the oppositeends of a spring with a spring constant 150 N/m and equilibriumlength 50 cm. By how much does the spring stretch? I am not looking for the answer, rather guidance on how to goabout finding the answer. Thanks a bunch :) Two 34-C charges are attached to the oppositeends of a spring with a spring constant 150 N/m and equilibriumlength 50 cm. By how much does the spring stretch? I am not looking for the answer, rather guidance on how to goabout finding the answer. Thanks a bunch :)

Explanation / Answer

    The force between the two charges is          F = (8.9*109N.m2/C2)(34*10-6C)2/(0.50m)     We know that                k = F/x              The inceased length of the spring is                      x = F/k Here k = 150 N/m Substitute the values for x.

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