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A 5.30 m length of 2.2 mm diameter wire carries a 775 mA current when 24.0 mVis

ID: 1762309 • Letter: A

Question

A 5.30 m length of 2.2 mm diameter wire carries a 775 mA current when 24.0 mVis applied to its ends. Assume the drift velocity is 1.7 ×10-5 m/s. (a) Determine the resistance R of thewire.
1

(b) Determine the resistivity, .
2 ·m

(c) Determine the magnitude of the current density j.
3 A/m2

(d) Determine the magnitude of the electric field inside thewire.
4 V/m

(e) Determine the number n of free electrons per unitvolume.
5 m-3 (a) Determine the resistance R of thewire.
1

(b) Determine the resistivity, .
2 ·m

(c) Determine the magnitude of the current density j.
3 A/m2

(d) Determine the magnitude of the electric field inside thewire.
4 V/m

(e) Determine the number n of free electrons per unitvolume.
5 m-3

Explanation / Answer

a) V = iR      R = V / i            =  24.0 mV / 775 mA            = 0.0309 b) = RA / L        = 0.0309*0.0000152m2 /5.30 m        = 8.86 x 10-8-m c) J = i / A       = 775 mA / 0.0000152m2       = 50986 A/ m2 d) E = J        = 50986 A/ m2* 8.86 x 10-8 -m        = 4.517 x 10-3V/m e) n = J / vde = ........ d) E = J        = 50986 A/ m2* 8.86 x 10-8 -m        = 4.517 x 10-3V/m e) n = J / vde = ........
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