When you push a 1.95 kg bookresting on a tabletop it takes 1.80 N to start the b

Question

When you push a 1.95 kg bookresting on a tabletop it takes 1.80 N to start the book sliding. Once it issliding, however, it takes only 1.50 N to keep the book moving withconstant speed. What are the coefficients of static and kineticfriction between the book and the tabletop?
static kinetic



static kinetic


static kinetic

Explanation / Answer

For static friction :            F - fs= 0            F =smg            ==>s = F /mg                        = 1.5 / 1.95*9.8                        = 0.0784 For kinetic friction :         F - fk = 0            F =kmg            ==>k = F /mg                        = 1.80 / 1.95*9.8                        = 0.094

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