A 1500 kg car starts from rest and drives around a flat 50 mdiameter circular tr

Question

A 1500 kg car starts from rest and drives around a flat 50 mdiameter circular track. The forward force provided by that car'sdrive wheels is a constant 1000 N. (a) What are the magnitude and direction of the car'sacceleration at t=10s? Give the direction as an angle from ther-axis. (I got 1.78 m/s2, and 76.39 degrees, not sure ifthat's right) (b) If the car has rubber tires and the track is concrete, atwhat time does the car begin to slide of of the circle? ```` A 1500 kg car starts from rest and drives around a flat 50 mdiameter circular track. The forward force provided by that car'sdrive wheels is a constant 1000 N. (a) What are the magnitude and direction of the car'sacceleration at t=10s? Give the direction as an angle from ther-axis. (I got 1.78 m/s2, and 76.39 degrees, not sure ifthat's right) (b) If the car has rubber tires and the track is concrete, atwhat time does the car begin to slide of of the circle? ````

Explanation / Answer

a) speed of the car after 10sec                 v = at a = accleration , t = timeperiod car acceleration will alwaysdirects to wards the centre of the circulat track distance travelled by the carin time ' t '     S = at^2 /2 angular displacement = ( S/2r) * 2. b)velocity of the car at which it startslipping off the track                   v = (mg)    time at which the car startslipping off the track                 t = v / a       =coefficeitn of friction between rubber tyre and concretetrack.

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