A small object of mass m=4kg is subject to a simultaneous action ofthree forces

Question

A small object of mass m=4kg is subject to a simultaneous action ofthree forces given by
(in unit vector notation with all numbers in units of Newtons)

F1=5i+3j 4k

F2= 2i+k

F3=7i+j 2k

1.What is the acceleration vector.
2.If during the action of the forces the object changes itslocation from r1=4i to r2=-4i what is thework done by force F1 on this displacement?


F1=5i+3j 4k
F2= 2i+k
F3=7i+j 2k

1.What is the acceleration vector.
2.If during the action of the forces the object changes itslocation from r1=4i to r2=-4i what is thework done by force F1 on this displacement?


1.What is the acceleration vector.
2.If during the action of the forces the object changes itslocation from r1=4i to r2=-4i what is thework done by force F1 on this displacement?

Explanation / Answer

mass m = 4 kg forces F1=5i+3j 4k          F2= 2i+k         F3=7i+j 2k net force F = F1+F2 +F3                  = 10 i +4j-5k Accleration vector a = F / m                                = 2.5 i + j -1.25 k (2). displacement S = r2-r1 = -4i-4i = -8 i So, work done by force F1 on the displacement W = F1 .S                                                                               = ( 5 i + 3 j -4 k ) . -8i                                                                               = 5 * -8                                                                               = -40 J

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