Question: Straight from home, you bike 24km north in 2.5hours, then turn around

Question

Question: Straight from home, you bike 24km north in 2.5hours, then turn around and pedal stright home in 1.5. What is yourdisplacement at the end of the first 2.5 hours and your averagevelocity? My problem: How do you set up the picture? Like how do theytake 2.5 hours one way and only 1.5 the next? Speed up right? Sowould there be any displacement at all since its a straightline? Question: Straight from home, you bike 24km north in 2.5hours, then turn around and pedal stright home in 1.5. What is yourdisplacement at the end of the first 2.5 hours and your averagevelocity? My problem: How do you set up the picture? Like how do theytake 2.5 hours one way and only 1.5 the next? Speed up right? Sowould there be any displacement at all since its a straightline?

Explanation / Answer

There wouldnt be any displacement at the end of the whole trip, However displacement after the first 2.5 hours is just simply24km north Now let's find the average velocity. Vav = (totaldistance / total time). Remember total distance is 24 x 2because its for both ways. Vav = [(24)(2)] / (2.5+1.5) = 12km/h

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