a.) At room temperature what is the strengthof the electric field in a 12-gauge

Question

a.) At room temperature what is the strengthof the electric field in a 12-gauge copper wire (diameter 2.05 mm)that is needed to cause a 2.00 A current to flow? E = ? b.) What field would be needed if the wirewere made of silver instead? E = ? (I don't know what equation to use orderive...) a.) At room temperature what is the strengthof the electric field in a 12-gauge copper wire (diameter 2.05 mm)that is needed to cause a 2.00 A current to flow? E = ? b.) What field would be needed if the wirewere made of silver instead? E = ? (I don't know what equation to use orderive...)

Explanation / Answer

. 01.   A = Area = *r2 02.   Ag = resistivity of silver= 1.59E-8 *m 03.   Cu = resistivity of silver= 1.72E-8 *m . 04.   A = *(1.025E-3 m)2 =3.300635782E-6 m2 05.   Assume a wire of length: d = 1 meter . 06.   RCu = *L/A = (1.72E-8*m)*(1 meter)/(3.3E-6 m2) = 5.211117232E-3 07.   VCu = R*I = (5.21E-3 )*(2.0Ampere) = 10.42223446E-3 volts 08.   ECu = V/d = (10.42223446E-3volts)/(1 meter) ˜ 10.4 milliVolts/meter . 09.   RAg = *L/A = (1.59E-8*m)*(1 meter)/(3.3E-6 m2) = 4.817253721E-3 10.   VAg = R*I = (4.82E-3 )*(2.0Ampere) = 9.634507441E-3 volts 11.   EAg = V/d = (9.634507441E-3volts)/(1 meter) ˜ 9.6milliVolts/meter . . 09.   RAg = *L/A = (1.59E-8*m)*(1 meter)/(3.3E-6 m2) = 4.817253721E-3 10.   VAg = R*I = (4.82E-3 )*(2.0Ampere) = 9.634507441E-3 volts 11.   EAg = V/d = (9.634507441E-3volts)/(1 meter) ˜ 9.6milliVolts/meter . 09.   RAg = *L/A = (1.59E-8*m)*(1 meter)/(3.3E-6 m2) = 4.817253721E-3 10.   VAg = R*I = (4.82E-3 )*(2.0Ampere) = 9.634507441E-3 volts 11.   EAg = V/d = (9.634507441E-3volts)/(1 meter) ˜ 9.6milliVolts/meter . .

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