Hello there. Need help on a circular motion problem? Question: Find the maximum

Question

Hello there. Need help on a circular motion problem? Question: Find the maximum speed the stone can attainwithout breaking the string. To find the velocity, the equation givenare: v = 2R/T    R=radius of thecircle    T= period (time for 1revolution) T is denoted by the period of a periodic motion.    Denote tension by FT. Fnet = m * (v^2/R) Fnet means: relation of net force toacceleration arad = 4^2R/T^2 arad is thecentripetal acceleration in terms of (T) period, the time for 1revolution. arad is thecentripetal acceleration in terms of (T) period, the time for 1revolution. I have a difficult time trying to findout how to get started and what variable to find first.    In this problem, I'm assumingthat given the equation Fnet = m*(v^2/R), I would thinkthat you would just plug in the given max tension (65N)in for Fnet and plug in the given values for R and m, get v^2 byitself on one side and square root the answer to get v. I have notplugged in the answer yet because I am unsure. Am I approachingthis problem correctly?        

Explanation / Answer

      Given that the mass of stone is m =0.700 kg       Length of stone is r = 0.900 m      The maximum tension in the string is T =65.0 N -------------------------------------------------------------------------- If the body moving in horizontal circle the tensionforce acting inwards and the outward force ismv2/r                            Then                                         T = mv2 /r                                        v = ( rT / m )1/2                                           = 9.14 m/s           This is themaximum speed of the stone .

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