Your friend has a pair of fuzzy dice with a mass of 1.24 g hanging from his rear

Question

Your friend has a pair of fuzzy dice with a mass of 1.24 g hanging from his rear-view mirror. (a) When he accelerates from a stoplight, thedice deflect backward toward the rear of the car hanging at anangle of 6.28° relative to thevertical. Find the tension in the string holding the dice. (b) At what angle to the vertical will thetension in the string be twice the weight of the dice? (a) When he accelerates from a stoplight, thedice deflect backward toward the rear of the car hanging at anangle of 6.28° relative to thevertical. Find the tension in the string holding the dice. (b) At what angle to the vertical will thetension in the string be twice the weight of the dice?

Explanation / Answer

   T cos 6.28 = m g
   T = m g / cos6.28
   = ( 1.24x10-3 ) (9.8) / cos 6.28
   = 0.0122N
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b) Fro the same equation
   T cos ( theta) = m g
   Given that T =2 mg
   2mg cos ( theta) =m g
   cos ( theta) = (1/2)
   theta =cos-1( 1/2)
      = 60

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