A uniform electric field of magnitude 250 V/mis directed in the negative x direc

Question

A uniform electric field of magnitude 250 V/mis directed in the negative x direction. A -15.1 uC chargemoves from the origin to the point (x, y) = (24.3cm, 48.9 cm). (a)What was the change in the potential energy of thischarge? (b) Through what potential difference did the chargemove?

For potential energy do you get the distance from the coordinatepoints or is that for potential difference? Also, I'm not sure howthe 250 V/m plays into the problem. Do you just use a regularpotential energy equation Wc = -U? No chargeequations? Thanks, and I rate every answer!

Explanation / Answer

(a)    the change in potential difference willbe    V = (1 / 4 o)(- 15.1 x 10-6 C) / r    (0, 0) = (x1,y1)    (24.3 cm, 48.9 cm) = (x2,y2)    where r = [(x2 -x1)2 + (y2 -y1)2]                = ......... cm                 =......... m (b)    V = E r    (24.3 cm, 48.9 cm) = (x2,y2)    where r = [(x2 -x1)2 + (y2 -y1)2]                = ......... cm                 =......... m (b)    V = E r

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