A large grinding wheel in the shape of a solid cylinder ofradius 0.333 m is free

Question

A large grinding wheel in the shape of a solid cylinder ofradius 0.333 m is free t roatate on a frictionless , verticleaxle. A comnstant tangential force of 210 n is applied to its edgeto causes the wheel to have an angular acceleration of 1.110rad/s^2 what is the moment of inertia on thewheel?__________________kg.m^2 what is the mass of the wheel?_________________kg if the wheel starts from rest, what is its angular velocituyafter 4.90 s have elapsed asssuming the force is acting during thattime?____________________ rad/s A large grinding wheel in the shape of a solid cylinder ofradius 0.333 m is free t roatate on a frictionless , verticleaxle. A comnstant tangential force of 210 n is applied to its edgeto causes the wheel to have an angular acceleration of 1.110rad/s^2 what is the moment of inertia on thewheel?__________________kg.m^2 what is the mass of the wheel?_________________kg if the wheel starts from rest, what is its angular velocituyafter 4.90 s have elapsed asssuming the force is acting during thattime?____________________ rad/s

Explanation / Answer

radius r = 0.333 m tangential force F = 210 N angular accleration = 1.11 rad ./ s ^ 2 Torque T = Fr                 =69.93 N m we know T = I from this moment of inertia I = T /                                            = 63 kg m ^ 2 we know I = ( 1/ 2) m r ^ 2 from this mass m = 2I / r ^ 2                           = 1136.27 kg (b) . initial angular speed w = 0 rad / s time t= 4.9 s from the relarion w ' = w + t angular speed after time t ius w ' = t =1.11* 4.9= 5.439 rad / s (b) . initial angular speed w = 0 rad / s time t= 4.9 s from the relarion w ' = w + t angular speed after time t ius w ' = t =1.11* 4.9= 5.439 rad / s

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