The 80 k g student in the figure ( Figure 1 ) balances a 1100 k g elephant on a
ID: 1767548 • Letter: T
Question
The 80kg student in the figure(Figure 1) balances a 1100kg elephant on a hydraulic lift.
A) What is the diameter of the piston the student is standing on? Answer = 0.54m
B) When a second student joins the first, the piston sinks 35
cm . What is the second student's mass?
*I can't get part B. Can you please help me out? Thanks! :)
The 80kg student in the figure(Figure 1) balances a 1100kg elephant on a hydraulic lift. What is the diameter of the piston the student is standing on? Answer = 0.54m When a second student joins the first, the piston sinks 35 cm . What is the second student's mass? *I can't get part B. Can you please help me out? Thanks! :)Explanation / Answer
As both are at same level pressure is same
=> mg/A1 = Mg/A2 => 80 x g/A1 = 1100 x g/A2 => A1 = (80/1100 ) x A2
=> d1^2 = (80/1100) x d2^2
=> d1 = 0.26968 x d2 = 0.26968 x 2
=0.539 m = 0.54 m
if m is the mass of the second student, then
mg/A1 is the excess pressure .
This excess pressure =(density of oil)xg x height raised in right piston.
h1A1 = h2 A2 => h2 = h1(A1/A2) = 35 (80/1100) =2.5454 cm
=> m = density of oil x 2.5454 x 10^(-2) x 9.8
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