%3Cp%3E%3Cspan%20class%3D%22c1%22%3E****I%20JUST%20NEED%20G%3C%2Fspan%3E%3C%2Fp%
ID: 1768081 • Letter: #
Question
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a) x = x0 + vx0*t + 1/2*a*t^2 = 0.140 + 0.190*3.10 + 1/2*(-.380)*(3.10)^2 = -1.097m
b) v = vx0 + a*t = 0.190 + (-.380)*3.10 = -0.988m/s
c) Here we have x = A*sin(?t);;so v = ?A*cos(?t) ...and a = -?^2A*sin(?t)
So initially we have x = 0.140 = A*sin(?t); v = 0.190 = ?*A*cos(?t) and a = -0.380 = -?^2A*sin(?t)
So a /x = 0.380/0.140 = ?...so ? = 2.71
Now square the a eqn and the v eqn and add them
x^2 = A^2*sin^2(?t)
v^2 = ?^2A^2*cos^2(?t)
adding we get x^2 + v^2/?^2 = A^2*(sin^2 + cos^2) = A^2
Therefore A = sqrt((x^2 + v^2/?^2)) = sqrt((0.140^2 + 0.190^2/ 2.07^2)) = 0.167m
So x = 0.167m*sin(2t) and v = 2.07*0.167*cos(2t) = 0.345*cos(2t)
Note angles are inradians
So at t = 3.10s x = 0.167*sin(2.07*3.1) = 0.01866m
and v = 0.345*cos(2.07*3.1) = -0.342m/s
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