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ID: 3899844 • Letter: #

Question

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Explanation / Answer

The formulae for components of acceleration of a particle moving in a curve with polar co-ordinates (r, t) are:
Normal: r''- r(t')^2
Tangential: rt''+ 2r't'


For circular motion r' and r'' are zero, yielding:
Normal: - r(t')^2
Tangential: rt''

For the flywheel, the normal acceleration of a particle on the rim at the start is:
0, as t' is initially 0.

The tangential acceleration is:
0.300 * 0.600
= 0.18 m/s^2.


The resultant acceleration is the same as the tangential.

When the flywheel has rotated through pi/3 (= 60 deg):
(t')^2 = 2 * 0.600 * pi/3
t = 1.12 rad/s.

The normal acceleration is:
- 0.300 * 2 * 0.6 * pi / 3
= - 0.38 m/s^2.

The tangential acceleration is still 0.18 m/s^2, as it is constant.

The resultant accleration is of magnitude:
sqrt(0.38^2 + 0.18^2)
= 0.42 m/s^2.