%3Cp%20class%3D%22c2%22%3E%3Ca%20class%3D%22c1%22%3EMultiple-Concept%20Example%0
ID: 3899665 • Letter: #
Question
%3Cp%20class%3D%22c2%22%3E%3Ca%20class%3D%22c1%22%3EMultiple-Concept%20Example%0A9%3C%2Fa%3E%20reviews%20the%20concepts%20that%20play%20roles%20in%20this%20problem.%0AThe%20drawing%20shows%20a%20collision%20between%20two%20pucks%20on%20an%20air-hockey%0Atable.%20Puck%20A%20has%20a%20mass%20of%200.0210%20kg%20and%20is%20moving%20along%20the%20x%0Aaxis%20with%20a%20velocity%20of%20%2B4.40%20m%2Fs.%20It%20makes%20a%20collision%20with%20puck%0AB%2C%20which%20has%20a%20mass%20of%200.0420%20kg%20and%20is%20initially%20at%20rest.%20The%0Acollision%20is%20not%20head-on.%20After%20the%20collision%2C%20the%20two%20pucks%20fly%0Aapart%20with%20the%20angles%20shown%20in%20the%20drawing.%20Find%20the%20speed%20of%20(a)%0Apuck%20A%20and%20(b)%20puck%20B.%3C%2Fp%3E%0A%3Cdiv%3E%3Cbr%20%2F%3E%3C%2Fdiv%3E%0AExplanation / Answer
The first thing to keep in mind is that momentum is conserved forthe X and the Y direction, INDEPENDENTLY. So you will need toset up two equations where initial momentum = final momentum- onefor the x and one for the y.
Because puck A is coming in horizontally, all of the initialmomentum is in the x direction. So for the Y the final ymomentums will be equal and opposite, because when added togetherthey must equal zero. Use components to define the valuesV(Y) for A would be V(A)sin65.
You will end up with two equations for the two variables and thenyou can solve simultaneous equations.
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