A major league catcher catches a fastball moving at 80.0mi/h and his hand and gl

ID: 1768531 • Letter: A

Question

A major league catcher catches a fastball moving at 80.0mi/h and his hand and glove recoil 10.0 cm in bringing the ball to rest.

Part A

If it took 0.00500s to bring the ball (with a mass of 300g ) to rest in the glove, what is the of the change in momentum of the ball in kg?m/s ?

Part B

What is the direction of the change in momentum of the ball in N?

Part C

Find the magnitude of the average force the ball exerts on the hand and glove?

Part D

Find the direction of the average force the ball exerts on the hand and glove?

1- the same as the initial velocity of the ball 2- opposite to the initial velocity of the ball

Given,

intial velocity, v0=80.0mph=35.756m/s

m=0.3kg

2. 2-

opposite to the initial velocity of the ball

3. Force applied= change in momentum/time=10.727/0.005=2145.33N

4. 1-opposite to the initial velocity of the ball

2. 2-

opposite to the initial velocity of the ball

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.