1. A wheel turns through 40 revs as it slows from an angular speed of 1.5 rad/s
ID: 1769576 • Letter: 1
Question
1. A wheel turns through 40 revs as it slows from an angular speed of 1.5 rad/s to a stop. A.) assuming a constant angular acceleration, find the time for it to come to a rest. B.) what is its angular acceleration?2.in a railroad accident a boxcar wearing weighing 200kN and traveling at 3.0 m/s on horizontal track slams into a stationary car ween 400kN. the collision is inelastic. how much energy is transferred from kinetic to other forms in the collision?
3.A disc of mass m slides in a horizontal circle of radius r on a frictionless table attached to a hanging cylinder of mass M by a cord through a hole in the center of the table. what speed v of the disc will allow the cylinder to fall vertically with an acceleration equal to half that of gravity? 1. A wheel turns through 40 revs as it slows from an angular speed of 1.5 rad/s to a stop. A.) assuming a constant angular acceleration, find the time for it to come to a rest. B.) what is its angular acceleration?
2.in a railroad accident a boxcar wearing weighing 200kN and traveling at 3.0 m/s on horizontal track slams into a stationary car ween 400kN. the collision is inelastic. how much energy is transferred from kinetic to other forms in the collision?
3.A disc of mass m slides in a horizontal circle of radius r on a frictionless table attached to a hanging cylinder of mass M by a cord through a hole in the center of the table. what speed v of the disc will allow the cylinder to fall vertically with an acceleration equal to half that of gravity?
2.in a railroad accident a boxcar wearing weighing 200kN and traveling at 3.0 m/s on horizontal track slams into a stationary car ween 400kN. the collision is inelastic. how much energy is transferred from kinetic to other forms in the collision?
3.A disc of mass m slides in a horizontal circle of radius r on a frictionless table attached to a hanging cylinder of mass M by a cord through a hole in the center of the table. what speed v of the disc will allow the cylinder to fall vertically with an acceleration equal to half that of gravity?
Explanation / Answer
a)let the angular acceleration be x.so,
w^2=2*x*rev
or 1.5^2=(40*2*pi)*2*x
or x=4.47*10^-3 rad/s^2
let the time be t.so,
t=w/x
=1.5/(4.47*10^-3)
=335.57 s
2)conserving momentum,
fianl velocity=200*3/(200+400)
=1 m/s
so loss of energy = 0.5*200*3^2 - 0.5*600*1^2
=600 J
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