Thank you Part A Suppose that an asteroid traveling straight toward the center o

Question

Thank you

Part A Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth's mass M, for the day to become 26.0% longer than it presently is as a result of the collision? Assum e that the asteroid is very small compared to the earth and that the earth is uniform throughout. m= 10.1 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining

Explanation / Answer

Applying angular momentum conservation,

Ii wi = If w f

Ii = (2 M R^2 / 5)

wi = 2 pi / Ti

Tf = 1.26 Ti

wf = 2 pi / (1.26 Ti) = wi/1.26

If = (2 M R^2 / 5 + m R^2)

putting in,

0.4 M R^2 wi = (0.4 M R^2 + m R^2) wf

0.4 M = (0.4 M + m )(1/1.26)

m = 0.104 M

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