A 1000 N uniform boom is supported by a cable perpendicular to the boom, as in F

Question

A 1000 N uniform boom is supported by a cable perpendicular to the boom, as in Figure P8.26. The boom is hinged at the bottom, and a 2100 N weight hangs from its top. 25 Figure P8.26 (a) Find the tension in the supporting cable. 3141x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N (b) Find the components of the reaction force exerted on the boom by the hinge. 2.847 to the rgh Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N 37299 your solution from the beginning and check each step carefully. N upward Your response differs significantly from the correct answer. Rework

Explanation / Answer

a] Balancing torque about hinge, T sin ( 180 -65 -25 degree) *3/4 L = mg sin (90-65 degree) *L/2 +  W sin (90-65 degree) *L

T = (2100* sin 25 degree + 1000*sin 25 degree *0.5)4/3

= 1465 N answer

b] Horizontal force by tension is at left, so force at floor be towards right.

magnitude = T cos 25 degree = 1465 cos 25 degree = 1328 N

vertical component magnitude = 1000 +2100 -1465 sin 25 degree = 2481 N

direction = upward in order to balance the weight.

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