Free response. A uniform magnetic field of strength 0.7 T points out of the page

Question

Free response. A uniform magnetic field of strength 0.7 T points out of the page. A current of magnitude 6 mA flows through the circuit in the direction indicated. The net force on the part of the circuit drawn with a bold line has a y-component of magnitude-0 -N They components cancel out and has a total magnitude of 0.378 mN. F- ilB-6 10 *0.7T 0.09m) Note that there are two parts of the triangle written in bold. We want you to give the sum of the two. Hint: write a vector that describes the flow of the current. Do the cross product to get each of the components. I used the determinant method to do it. You may have another reliable way of doing it. The vector form of the first wire is 12i-9 Sem 2 cm

Explanation / Answer

The first wire length segment can be given as,

  L1 = 12i - 9j cm [x value of L1is 12 and y value is square root of (152-122) =9]

The 2nd wire segment can be given as,

  L2 = -12i cm [as the current is flowing from right to left, hence negative]

The net force, F = i(L1xB+L2xB)

B = B k = 0.7 k

F = 0.006x(- 0.12x0.7 j - 0.09x0.7 i + 0.12x0.7 j)

F = - 0.006x0.09x0.7 i N = - 0.378 i mN (leftwards)

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