Question 1 3 pts Calculate the Rotational Inertia (Moment of Inertial about its

Question

Question 1 3 pts Calculate the Rotational Inertia (Moment of Inertial about its axis of a disk of diameter D-41m. mass M 13 kg, and thickness T 12 cm. Question 2 2 pts You have a solid cyfinder of mass M and radius R, and a Ring (hollow cylinder) also of mass M, and outer radius R. Which af the two will have the greater Moment of inertia? D The Rine G They wil hove same value G The cyinder 2 pts Question 3 Calculate the moment of inertia of a unform rod of mass 3.9 kg and length 34 cmatout an is perpendicular to the rod and passes through its center.(give answer in kgm) tat Question 4

Explanation / Answer

1)

rotational moment of inertia , I = 0.50 * M * R^2

rotational moment of inertia , I = 0.50 * 13 * (4.1/2)^2

rotational moment of inertia , I = 27.3 Kg.m^2

the rotational moment of inertia is 27.3 Kg.m^2

2)

moment of inertia of ring = M * R^2

moment of inertia of Disk = 0.50 * M * R^2

the moment of inertia of ring is larger

the correct option is The Ring

3)

moment of inertia of rod = 1/12 ML^2

moment of inertia of rod = 1/12 * 3.9 * 0.34^2

moment of inertia of rod = 0.038 Kg.m^2

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