\'-- Sapling Online Homework Kansas State University-PHYS × Physics question! Ch
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'-- Sapling Online Homework Kansas State University-PHYS × Physics question! Chegg.com > Physics question IChegg.com × www.saplinglearning.com/ibiscms/modibis/view.php?id=4637424 120% a. Search Sapling Learning macmillan learning ? Taylor Garrett Jump to... Jeremy Schmit at Kansas State University Points Possit A transcription factor is a molecule that binds to a specific DNA sequence in order to control the expression of the nearby genetic material. In this problem we will look at the process by which the factor finds the correct sequence to bind to. Assume that factor can bind loosely to a DNA sequence that does not match the target sequence. After every 10 ns the molecule will move 1 base pair with a 50/50 chance that the move is to the left or to the right Grade Categ 4 5 Policies: After 100 ns, what is the probability that the transcription factor is 6 base pairs to the left of where it started? (hint: treat each step like a coin flip) You can che You can view give up on a You can kee until you get You lose 5% answer in yo attempt at t Number Where is the most likely place for the factor to be after 100 ns? eTextbook To answer this question number each site with an integer so that the starting site is site zero sites to the right are positive, and sites to the left are negative.) O Help With O Web Help Previous Give Up & View Solution Check Answer Next Exit O Technical ' Hint O Type here to search 7:05 PM 11/27/2017 2Explanation / Answer
Part-A
Within 100ns, the number of movements = 100ns / 10ns = 10
So in these 10 movements, net position should be 6 positions left.
This is possible when it has travelled total 8 positions left and 2 positions right, irrespective of the order.
p for left = p for right = 0.5
P(left 6) = 10C8*(0.5)8 *(0.5)2 = 0.0439
Part-B
Most likely place is the same place where it starts as at each and every movement, there is an equal chance of moving left or right, hence, on an avergae we can expect the position to remain the same as:
Expected change = -1*0.5 + 1*0.5 = 0
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