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ID: 1828430 • Letter: #

Question

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Problem 2.124

"margin: 0px 0px 0.75em; padding: 0px; height: 1px;">Will rate.

Thanks ahead. The answer I tried was 84j + 28k which I think is

close.



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Part

A

"margin: 0px 0px 0.75em 2em; padding: 0px;">Determine the projected

component of force

src="http://session.masteringengineering.com/render?expr={f{F}}_{AB}"

class="done" />along the axis of strutAO.

Express the result as a Cartesian vector.

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1

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Express your answer in

terms of the unit vectors

src="http://session.masteringengineering.com/render?expr={f+i}"

"http://session.masteringengineering.com/render?expr={f+j}"

"http://session.masteringengineering.com/render?expr={f+k}"

class="done" />using two significant figures.

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"gadget genericFlash solutionSymbolic" style=

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"margin: 0px; padding: 2px;">

"({f{F}}_{AB})_{AO}" align="middle" src=

"http://session.masteringengineering.com/render?expr=({f{F}}_{AB})_{AO}"

class="done" />=

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width="375" height="60" style=

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"margin: 0px; padding: 2px;">

"middle" src=

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class="done" />



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What would the answer be for Fac



Explanation / Answer

Find component for AO
AO = ( 0, -6, -2)
need to normalize
AO = 1/sqrt(6^2 + 2^2 ) (0,-6,-2)
= 1/sqrt(40) <0,-6,-2>

Find components for FAC
x= 5 cos 60
y=-6
z= 5 sin 60 - 2
FAC x = x/L F = 5 cos 60 * 60 / sqrt( (5cos60)^2 +6^2 + (5 sin 60 - 2)^2)=21.72
FAC y = y/L F = -6 * 60 / sqrt( (5cos60)^2 +6^2 + (5 sin 60 - 2)^2)= -52.14
FAC z = z/ L F = (5 sin 60 - 2)* 60 / sqrt( (5cos60)^2 +6^2 + (5 sin 60 - 2)^2)= 20.25

to find project we calculate dot product between FAC and AO
FAC * AO = FACx AOx + FACy AOy + FACz AOz
= 21.72 * 0 + -52.14*1/sqrt(40)*-6 + 20.25 * 1/sqrt(40)*-2 = 43.06