oo0 Sprint 12:28 PM session.masteringphysics.com C Problem 11.46 A68 kg hiker wa

Question

oo0 Sprint 12:28 PM session.masteringphysics.com C Problem 11.46 A68 kg hiker walks at 5.0 km/h up a 8% slope. The indicated incline is the ratio of the vertical distance and the horizontal distance expressed as percentage. What is the necessary metabolic power? Hint: You can model her power needs as the sum of the 380 W power to walk on level ground plus the power needed to raise her body by the appropriate amount. Assume that the efficiency of the body in using energy is 25 Express your answer to two significant figures and include the appropriate units. %. P508W Submit My Answers Give Up Incerrect: Try Again In

Explanation / Answer

v = 5 km/hr = 1.39 m/s

theta = tan-1(0.08) = 4.57 deg

P = P0 + [ Fv / efficiency]

= P0 + [ (m g sin theta * v) / efficiency]

= 380 + [ (68 * 9.8 * sin 4.57 * 1.39) / 0.25]

P = 675.2 W

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