I don\'t need the answer to the question! I am trying to figure out how to what
ID: 1771129 • Letter: I
Question
I don't need the answer to the question! I am trying to figure out how to what equations from the given list were manipulated for the equation in the answer. 9. 450 N on the rope which is inclined at an angle of 38° to the horizontal. The floor exerts a kinetic friction force of 125 N on the crate as it moves across the floor. A worker drags a crate across a factory floor by pulling on a rope tied to the crate. The worker exerts a force of Calculate the magnitude of the acceleration of the crate if its weight is 960 N. (10points) a. 450N cos -125 N = 2.3552 = 2.35e 960 81 m/s b. Calculate the net work done on the box as it slides 3.25 m across the floor. (5 points) wwer = maar cos0°= 960 N (234627m)(2.35 m)=7401 9.81 10, A box of mass m = 2.57 kg is sitting initially at rest on top of a co constant of 4250 N/mExplanation / Answer
a] The net force on the object will be:
Fnet = Fcos38 - 125 = ma
=> 450cos38 - 125 = (960/9.8)a
=> a = 2.344 m/s2.
b] Net Work Done = Net force x displacement
=> W = (960/9.8)(2.344) x 3.25 = 746.216 J.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.