5) A mass on a spring undergoes SHM. When the mass is at its maximum displacemen

Question

5) A mass on a spring undergoes SHM. When the mass is at its maximum displacement from equilibrium, its instantaneous velocity A) is zero. B) is less than maximum, but not zero. C) is maximum D) cannot be determined without mass information given. E) cannot be determined without spring constant information given. 6) A mass on a spring undergoes SHM. When the mass passes through the equilibrium position, its instantaneous velocity A) is zero. B) is less than maximum, but not zero. C) is maximum. D) cannot be determined without mass information given E) cannot be determined without spring constant information given. 7) A mass is attached to a spring and oscillates with a period T. If the mass is halved, what is the new period? A) 3T B) T73 C) T D)TV2 8) The quartz crystal in a digital watch has a frequency of 42.8 kHz. What is its period of oscilla- tion? A) 3.05 x 10-5 B) 2.34 × 10-5 s C) 9.58 x 10-5 D) 1.91 × 10-4 s E) None of these 9) A harmonic wave travels with a speed of 200 m/s and has a wavelength of 1.6 m. What is the frequency of the wave? A) 25.0 Ha B) 40.0 Hz C) 125 Hz D) 80.0 Hz E) 250 Hz 10) A 4.00-m length of rope has a mass of 500 g. It is pulled taut with a force of 200 N. What is the speed of waves on the rope? A) 29.3 m/s B) 40.0 m/s C) 42.0 m/s D) 3.42 m/s E) None of these

Explanation / Answer

When the pendulum is at its maximum displacement, it can be considered to be at the turning point where its kinetic energy becomes momentarily zero ==> velocity at that instant is zero

5. Option - A

At the equilibrium position the instantaneous velocity will be maximum

6. Option - C

7. Option - D

T'=Txsqrt(2) because frequency = 1/T= 1/2pisqrt(k/m) which says frequency is inversly proportional to the square root of m.

8. Option - B

Timeperiod = 1/frequency

9. Option - C

frequency = velocity / wavelength = 125 Hz

10. velocity = sqrt(FL/m) = 40 m/sec

Option B

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