B) A ball is thrown from the top of a 40 m building with some initial horizontal

Question

B) A ball is thrown from the top of a 40 m building with some initial horizontal velocity. If the ball lands 55m from the base of the building and it takes 3.25 seconds to hit the ground, what are the components of the balls velocity just before it hits the ground ?
C2). On a level surface a football is kicked into the air with some initial velocity. If the ball lands 25 m from where it started and it takes 3 seconds to hit the ground , what is the magnitude of the balls inital velocity (m/s)?
D) a boat sails across a lake with an inital velocity Vo=(3m/s, 5m/s) and a constant acceleration of a=(-1m/s^2 , 2m/s^2). If this boat at the orgin, what are the components of its velocity at t=4s (m/s)? A4) A ball is thrown from the top of a 40 m building with an initial horizontal velocity. If the ball lands 30 m from the base of the building, what are the components of the ball's velocity just before it hits the ground (in m/s)? V× Vos B5) A ball is thrown from the top of a 40 m building with some initial velocity. If the ball lands 55 m from the base of the building and it takes 3.25 seconds to hit the ground, what are the components of the ball's velocity just before it hits the ground (in m/s)? C2) On a level surface a football is kicked into the air with some initial velocity. If the ball lands 25 m from where it started and it takes 3 seconds to hit the ground, what is the magnitude of the ball's initial velocity (in m/s)? D2) A boat sails across a lake with an initial velocity vo = (3 m/s, 5 m/s) and a constant acceleration of a = (-1 m/s , 2 m/s ). If this boat starts at the origin, what are the components of its velocity at t 4 s (in m/s)?

Explanation / Answer

A] Initial vertical velocity = uy = 0 m/s

vertical distance = H = 40 m

use, H = uyt + (1/2)gt2

=> 40 = 0 + (1/2)(9.8)t2

=> t = 2.8571 s

and horizontal distance covered = 30m

so, initial horizontal velocity will be: ux = 30/2.8571 = 10.5 m/s

Since there is no acceleration in the horizontal direction, therefore, the final horizontal velocity vx = 10.5 m/s

and final vertical velocity = vy = uy + gt = 9.8(2.8571) = 28 m/s.

These are the components of the velocity just before hitting the ground.

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