Children normally start to walk at around 12 months old and start to jump at aro

Question

Children normally start to walk at around 12 months old and start to jump at around 24 months old. A daredevil toddler takes a running start and jumps over a line-up of toys cars, takin off with a velocity of 2.5 m/s at an angle of 20 deg above the horizontal. Determine how high above the take-off point he will get at the highest point of the jump (i.e., the upward vertical displacements) and how far he will travel horizontally (i.e., the horizontal displacement). Assume take-off and landing are the same height.

How high will he jump (upward vertical displacement)?

How far will he jump (horizontal displacement)?

Explanation / Answer

u = 2.5
angle = 20 degree

At maximum height the vertical velocity will be 0
Hence,

uy = 2.5sin(20)

vy^2 = uy^2 + 2as
0 = (2.5sin(20) )^2 + 2*(-9.8)*sy
sy = 0.0373 m

Time taken to reach the maximum height :
v = u + at
0 = 2.5sin(20) + (-9.8)*t
t = 0.08725

Total time of jump = 2*t = 0.1745 sec

sx = ux*(2*t)
sx = 2.5cos(20)*0.1745
sx = 0.41 m

Please upvote if the answers are correct.

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