Chapter 08, Problem 022 Your answer is partially correct. Try again. A 68 kg ski

Question

Chapter 08, Problem 022 Your answer is partially correct. Try again. A 68 kg skier starts from rest at height H 24 m above the end of a ski jump ramp (see the figure). As the skier leaves the ramp, his velocity makes an angle of 31 with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless. (a) What is the maximum height h of his jump above the end of the ramp? (b) If he increased his weight by putting on a 10 kg backpack, what would h be? End of ramp (a) Numb 1 .689 (b) Nurmber T6.11

Explanation / Answer

Part A:

Energy is conserved

the velocity of the skier at the bottom of the slope.

KE(bottom) = PE(top)

½ mv2 = mgh

v = (2gh)

v = (2 x 9.8 x 24)

v = 21.6887067 m/s

H using projectile equation

H= (u2sin2)/2g

H = (21.68870672 * sin312)/(2*9.8)

H = (124.780288)/(2*9.8)

H = 6.36 m

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Part B:

KE(bottom) = PE(top)

½ mv2 = mgh

m is the same on each side so we can cancel it.

h is not dependend on m

so,

H = 6.36 m

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