A) at time t2=22.5 s what\'s the x-component of the dog\'s velocity? B) at tim t

Question

A) at time t2=22.5 s what's the x-component of the dog's velocity? B) at tim t2=22.5 s what's the y-component? C)what is the magnitude of dog's velocity? D) what's the direction (measured from the +x-axis toward the +y-axis the? A) at time t2=22.5 s what's the x-component of the dog's velocity? B) at tim t2=22.5 s what's the y-component? C)what is the magnitude of dog's velocity? D) what's the direction (measured from the +x-axis toward the +y-axis the? A dog running in an open field has components of velocity vr = 3.3 m/s and ty =-1.5 m/s at t me t! = 12.0 s . For the time interval from t1 = 12.0 s to t,-22.5 acceleration of the dog has magnituce 0.53 m/s2 and direction 32.0 measured from the -z -axis toward the +y-axis. s, the average

Explanation / Answer

a] x and y components of acceleration : ax = 0.53*cos 32 degree = 0.44946 m/s^2

ay =  0.53*sin 32 degree = 0.28086 m/s^2

Vx = vx + ax delta t = 3.3 + 0.44946 *(22.5-12) = 8.02 m/s

b] Vy = vy + ay delta t = -1.5 + 0.28086 *(22.5-12) = 1.45 m/s

c] magnitude V = sqrt(8.02^2+1.45^2) = 8.15 m/s

d] angle = arcsin (1.45/8.15) = 10.25 degree

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