In the picture below, the two wires carry current i1 and i2, respectively, with

Question

In the picture below, the two wires carry current i1 and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right.

TRUE/FALSE

A) If i1 is greater than i2, then the force on q is north.

B) If i2 = 0 and i1 is greater than zero, then the force on q points into the page.

C) If i2 = - i1 then the force on q equals zero.

D) If i1 = 0 and i2 is greater than zero, then the magnetic field near charge q points into the page

E) If i1 = - i2, then the wires repel each other.

F) If i1 = 0 and i2 is greater than zero then the force on q is south.

G) If v = 0, then the force on q is zero.

Explanation / Answer

Solution:

A) True , As the net magnetic field is inside so using flemming's left hand rule we can say the force will be in north direction.

B)False , As if i2 = 0 , then net magnetic field will be into the page so force will be in north , same as above.

C) False , if i2 = -i1 then net magnetic field will Not be zero so F is Not 0 (Negative sign will change the direction of current)

D) False , if i2 is not zero then magnetic field on charge q points out of the page( use Right hand thumb rule)

E)True

F) True ( use flemmings right hand rule)

G) Using F = qvB sin(theta) if v = 0 then force = 0 (True)

Please comment for Queries, or if i done some wrong considerations.

Thanks.

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