An 8.1-g bullet is fired into a 290-g block that is initially at rest at the edg

Question

An 8.1-g bullet is fired into a 290-g block that is initially at rest at the edge of a table of height 0.91 m as illustrated in the figure above. The bullet remains in the block, and after the impact the block lands 1.95 m from the bottom of the table. What was the speed of the block (with bullet embedded) just as it left the table? (in m/s) E: 4.01 OF: 4.53 2.46 2.78 3.14 3.55 5.12 5.78 Previous Tries Submit Answer Answer Submitted: Your final submission will be Tries 1/20 graded after the due date. What was the initial speed of the bullet? (in m/s) OF 25.99 37.69 54.65 79.25 114.91166.61 241.59 350.31

Explanation / Answer

a) d = v t + 1/2 a t2

0.91 = 1/2 * 9.81 * t2

t = 0.431 s

d = v t

1.95 = v * 0.431

speed of the block = 4.53 m/s [option F]

b) m1 v1i + m2 v2i = m1 v1f + m2 v2f

0.0081 * v1i + 0 = (0.0081 + 0.29) * 4.53

initial speed = 166.6 [option F]

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.