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Chrome File Edit View History Bookmarks People Window Help a 100% E Sun 11:41 PM Daniel Sasson e Chegg Study l Guided Solutio × The Expert TA | Human-like G × You . C à Secure l https://usu34ny.theexpertta.com/common/TakeTutorialAssignment.aspx : Appsa Facebook YouTube !Blackboard ily wire Other Bookmarks Chapter 21 Begin Date: 9130r2017 12:00:00 AM- -Due Date: 10/B2017 11:59:0O PM End Date: 12n9r201Y 12:00:00 AM (7%) Problem 10: Consider the circuit in the diagram, with sources of emf listed below 0.1 Randomized Variables 5.0 S 2012 e2 = 41 v 4=8.5 V 0.20 11 Assignment Status 78 Click here for detailed view i 0.0512 h ©theexpertta.com Problem Status 33% Part (a) Find 11 in amps 1Completed 2 Completed 3 Completed , I10.374 Grade Summary Deductions 0% 100% Completed Submissions Attempts remaining: 2 sinO 7 8 9 HOME cos0 cotan0 asin) acos0 tan() | | ( 5 Completed 6 Completed 7Completed 8 Completed 9Completed 10 Partial -per attempt) detailed view atan acotan( sinh0 1 23 - 0% 0 coshO tanh0 cotanhO Degrees Radians BACKSPACE DCLEAR Partial Submit Hint I give up! 12 Partial 3 Completed 4 Completed 15 Completed Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 0% deduction per feedback. 33% Part (b) Find 12 in amps - 33% Part (c) Find 13 in amps

Explanation / Answer

here,

using KVL in the upper loop

I1 * ( 5 + 20 + 0.1 ) - (0.5 + 40 ) * I2 = E1 - E2

I1 * ( 5 + 20 + 0.1 ) - (0.5 + 40 ) * I2 = 27 - 41 ....(1)

and

using KVL in the lower loop

I3 * ( 0.2 + 0.05 + 78) + (0.5 + 40 ) * I2 = E2 + E3 - E4

I3 * ( 0.2 + 0.05 + 78) + (0.5 + 40 ) * I2 = 41 + 8.5 - 46 ....(2)

and

using KCL

I1 + I2 = I3 ....(3)

from (1) , (2) and (3)

a)

I1 = - 0.56 A

b)

I2 = 0.19 A

c)

I3 = - 0.05 A

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