10/19/2017 11:55 PM75.7/100 () 10/s/2017 02:21 PM Question 15 of 15 Map Sapling

Question

10/19/2017 11:55 PM75.7/100 () 10/s/2017 02:21 PM Question 15 of 15 Map Sapling Learning A 22.1 kg mass is suspended by the cable assembly as shown in the figure below. The cables have no mass oftwr own The catie to the, leh (cable 1)ofthe mass makes an ange·6,.0.00. with the horizontal, ond the catie tothengt (catie 2) makes an angle, -343,f the mass is at rest what is the tensicn in each of the caties, T, and T7 The acceleration due to gravity is g 9 81 mis? Number ,-10 fiumber OPneveu, @o»" · 90eo Anseer O'.. ·" "(, , " Exit

Explanation / Answer

Here ,

for the tension T2

T2 * sin(theta2) - m * g = 0

T2 = 22.1 * 9.8/sin(34.3 degree)

T2 = 384 N

the tension T2 is 384 N

in the horizontal direction

T1 - T2 * cos(theta2) = 0

T1 - 384 * cos(34.3 degree) = 0

T1 = 317.5 N

the tension T1 is 317.5 N

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