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This print-out should have 46 questions. Multiple-choice questions may continue

ID: 1773656 • Letter: T

Question

This print-out should have 46 questions. Multiple-choice questions may continue on the next column or page find all choices before answering 004 (part 2 of 2) 10.0 points Find the position at t=58. 001 (part 1 of 2) 10.0 points 2.2-s =-8 A particle moves according to the equation z = (10 m/s) t2 where z is in meters and t is in seconds. Find the average velocity for the time i terval from 2.49 s to 4.2 s. 4. z,as =-10.5 Answer in units of m/s 002 (part 2 of 2) 10.0 points Find the average velocity for the time interval from 2.49 s to 2.59 s. Answer in units of m/s. 005 (part 1 of 2) 10.0 points Throw a ball upward from pont O with an initial speed of 62 m/s. 003 (part 1 of 2) 10.0 points An acceleration (in m/s2) has the time de- pendence shown on the graph below. The particle starts from rest (m = 0 m/s) at the origin (20 := 0 m). h . h" - Acceleration vs Time 62 m/s What is the maximu eration of gravity is -9.8 n Answer in units of m. ?The accel- 006 (part 2 of 2) 10.0 points If the speed of the ball as it passes point B is (62 m/s) = 31 m/s, what is the height hB Find the velocity at t-58. of B above O? Answer in units of m. 1. 4 m/s 007 (part 1 of 2) 10.0 points A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 3.8 s later with an initial speed of 74.48 m/s. They hit the ground at the same time. How long does it take the first stone to hit the ground? The acceleration of gravity is 9.8 m/s Answer in units of s.

Explanation / Answer

x = 10 t^2

x(2.49) = 10 (2.49^2)

x(4.2) = 10 (4.2^2)

average velocity = displacement / time

= 10 (4.2^2 - 2.49^2)/(4.2 - 2.49)

= 66.9 m/s

002.
v = 10 (2.59^2 - 2.49^2) / (2.59 - 2.49)

v = 50.8 m/s

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