eargulansp 10. A computer is reading data ro the disc,the centripetal accelerati
ID: 1773724 • Letter: E
Question
eargulansp 10. A computer is reading data ro the disc,the centripetal acceleration 120 0.050 m from the center of the disc? om a rotating CD-ROM. At a point that iso.030 m/from the center of n is 120 m/s What is the centripetal acceleration at a point that is 2. Le 0.030 2 1 14. At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of3.2 m/s, and an 83-kg person feels a 560-N force pressing against his back. What is the radius of the chamber?Explanation / Answer
formula for centripetal accleration is
a= v^2/r
a1 = v^2/r1
a2 = v^2/ r2
a2 = a1 ( r2/ r1) = 120( 0.05/0.03) =200 m/s^2
(2)
formula for centripetal force is
Fc= mv^2/ r
r = mv^2/ Fc
=83 kg ( 3.2)^2/560 N
=1.5 m
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