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biscms/mod/ibis/view.php?id-4546324 tate University-PHX | Kansas State University-PHYS ... saplinglearning.com saplinglearni 3/2017 05:00 PM 4 68.9/100 Grad Print (sa Periodic Table Calculator on 14 of 18 Sapling Learning Map df A thin stream of water flows smoothly from a faucet and falls straight down. At one point the water is flowing at a speed of v 1.23 m/s. At a lower point, the diameter of the stream has decreased by a factor of 0.841. What is the vertical distance h between these two points? Number h= cm Hint O Previous check Answer Next Exa about us careers privacy policy terms of use

Explanation / Answer

We know that

Q1 = Q2
A1v1 = A2v2
(0.25pi*d1^2)(v1) = (0.25pi*d2^2)(v2)
(d1^2)(v1) = (d2^2)(v2)
(d1^2)(1.23) = (0.841d1)^2(v2)
1.23 = (.841)^2v2
v2 = 1.74 m/s

Now we can use Bernoulli's to find the drop in height:
P1 + density(g)(y1) + 0.5(density)(v1)^2 = P2 + density(g)(y2) + 0.5(density)(v2)^2

P1 = P2 = Patm (this is because the stream is out in the open air in both points)
y1 = 0 (we will call the starting point the zero mark)

0.5(1000)(1.23)^2 = 1000(9.8)(y2) + 0.5(1000)(1.74^2)
y2 = -0.08 m

therefore, the water drops a height of 8 cm

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