(18%) Problem 4 : A student pushes a baseball of m = 0.14 kg down onto the top o
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(18%) Problem 4: A student pushes a baseball of m = 0.14 kg down onto the top of a vertical spring that has its lower end fixed to a table, compressing the spring a distance of d = 0.16 meters. The spring constant of the spring is k = 860 N/m. Let the gravitational potential energy be zero at the position of the baseball in the compressed spring.
parts a, b, and c please.
(1896) Problem 4: A student pushes a baseball of m = 0.14 kg down onto the top of a vertical spring that has its lower end fixed to a table, compressing the spring a distance of d= 0.16 meters. The spring constant of the spring is k= 860 Nm. Let the gravitational potential energy be zero at the position of the baseball in the compressed spring Randomized Variables m=0.14kg k = 860 N/m d=0.16 m > 33% Part (a) The ball is then released, what is its speed, v, in meters per second, just after the ball leaves the spring? Grade Summary Deductions Potential 0% 100% sin0 Submissions Attempts remaining: 10 (4% per attempt) 78 9 cos0 cotan0asin acos0 atan0 acotan0 sinh0 tan detailed view tanhO cotanhC END O Degrees O Radians EL CLEAR Submit Hint I give up! Hints: 3% deduction per hint. Hints remaining: Feedback: deduction per feedback. 33% Part (b) What is the maximum height, h, in meters, that the ball reaches above the equilibrium point? 33% Part (c) What is the ball's velocity, in meters per second, at half of the maximum height relative to the equilibrium point? -Explanation / Answer
a) v = d * sqrt [k / m] = 0.16 * sqrt [860 / 0.14]
speed v = 12.5 m/s
b) h = v2 / 2 g
h = 12.52 / (2 * 9.81)
max height = 8.0 m
c) hhalf = 8.0 / 2 = 4.0 m
v2 = (12.5)2 - (2 * 9.8 * 4.0)
ball's velocity v = 8.82 m/s
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