Review: Square Coil, Round Hole Due in 3 hours, 13 minutes single-turn wire coil

Question

Review: Square Coil, Round Hole Due in 3 hours, 13 minutes single-turn wire coil L 1.75 cm on a side is placed inside a solenoild that has a circular cross section of radlus r -2.85 cm, as The solenoid is 21.0 cm long and wound with 144 turns of wire. If the current in the solenoid is 3.45 A, find the flux through the coil. 121 10-31 Submit Answer Units required. Tries 0/10 Previous Tries If the current in the solenoid is reduced to zero in 3.49 s, calculate the magnitude of the average induced emf in the coil 1075 10-7V Submit Answer Tries 1/10 Previous Tries Send Fe This discussion is closed.

Explanation / Answer

field due to solenoid,

B = u0 n I = u0 (N / L ) I

and flux = B A

= (4pi x 10^-7) (144/0.21) (3.45) (0.0175^2)

= 9.104 x 10^-7 Wb .......Ans

induced emf = d(flux)/dt

= (9.104 x 10^-7 - 0) / 3.49

= 2.61 x 10^-7 Volt

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